C 语言实例 - 实现简单的计算器
实现加减乘除计算。
实例
# include <stdio.h>
int main() {
char operator;
double firstNumber,secondNumber;
printf("输入操作符 (+, -, *, /): ");
scanf("%c", &operator);
printf("输入两个数字: ");
scanf("%lf %lf",&firstNumber, &secondNumber);
switch(operator)
{
case '+':
printf("%.1lf + %.1lf = %.1lf",firstNumber, secondNumber, firstNumber + secondNumber);
break;
case '-':
printf("%.1lf - %.1lf = %.1lf",firstNumber, secondNumber, firstNumber - secondNumber);
break;
case '*':
printf("%.1lf * %.1lf = %.1lf",firstNumber, secondNumber, firstNumber * secondNumber);
break;
case '/':
printf("%.1lf / %.1lf = %.1lf",firstNumber, secondNumber, firstNumber / secondNumber);
break;
// operator doesn't match any case constant (+, -, *, /)
default:
printf("Error! operator is not correct");
}
return 0;
}
输出结果为:
输入操作符 (+, -, *, /): * 输入两个数字: 4 5 4.0 * 5.0 = 20.0
C 语言实例
big_tree
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豪华版计算器,如果加上图形库就跟好了(下面省略没写)。
#include <stdio.h> int get_option(); void print_result(int num1,int num2,int result,int option); int main(void) { int done = 0; int option,num1,num2,result; while(!done) { option = get_option(); if(option == 5) { done = 1; } else { do { printf("\n请输入两个数:"); scanf("%d %d",&num1,&num2); if(option == 4 && num2 == 0) { printf("\n对不起,除数不能为零"); } else { switch(option){ case 1: result = num1 + num2; break; case 2: result = num1 - num2; break; case 3: result = num1 * num2; break; case 4: result = num1 / num2; } print_result(num1,num2,result,option); } }while(option == 4 && num2 == 0); } } return 0; } int get_option() { int option; do { printf("\n ****************"); printf("\n * 1.加法 *"); printf("\n * 2.减法 *"); printf("\n * 3.乘法 *"); printf("\n * 4.除法 *"); printf("\n * 0.退出 *"); printf("\n ****************"); printf("\n请输入您需要的功能:"); scanf("%d",&option); if(option <1 || option > 5) { printf("对不起您输入的数字有误,请重新输入。\n"); } }while(option <1 || option > 5); return option; } void print_result(int num1,int num2,int result,int option){ char operator; switch(option){ case 1: operator = '+'; break; case 21: operator = '-'; break; case 3: operator = '*'; break; case 4: operator = '/'; break; } printf("\n** %d %c %d = %d **\n",num1,operator,num2,result); }big_tree
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