C 语言实例 - 八进制与二进制相互转换
C 语言实例八进制与二进制相互转换。
实例 - 二进制转换为八进制
#include <stdio.h>
#include <math.h>
int convertBinarytoOctal(long long binaryNumber);
int main()
{
long long binaryNumber;
printf("输入一个二进制数: ");
scanf("%lld", &binaryNumber);
printf("二进制数 %lld 转换为八进制为 %d", binaryNumber, convertBinarytoOctal(binaryNumber));
return 0;
}
int convertBinarytoOctal(long long binaryNumber)
{
int octalNumber = 0, decimalNumber = 0, i = 0;
while(binaryNumber != 0)
{
decimalNumber += (binaryNumber%10) * pow(2,i);
++i;
binaryNumber/=10;
}
i = 1;
while (decimalNumber != 0)
{
octalNumber += (decimalNumber % 8) * i;
decimalNumber /= 8;
i *= 10;
}
return octalNumber;
}
输出结果为：
输入一个二进制数: 101001 二进制数 101001 转换为八进制为 51
实例 - 八进制转换为二进制
#include <stdio.h>
#include <math.h>
long long convertOctalToBinary(int octalNumber);
int main()
{
int octalNumber;
printf("输入一个八进制数: ");
scanf("%d", &octalNumber);
printf("八进制数 %d 转二进制为 %lld", octalNumber, convertOctalToBinary(octalNumber));
return 0;
}
long long convertOctalToBinary(int octalNumber)
{
int decimalNumber = 0, i = 0;
long long binaryNumber = 0;
while(octalNumber != 0)
{
decimalNumber += (octalNumber%10) * pow(8,i);
++i;
octalNumber/=10;
}
i = 1;
while (decimalNumber != 0)
{
binaryNumber += (decimalNumber % 2) * i;
decimalNumber /= 2;
i *= 10;
}
return binaryNumber;
}
输出结果为：
输入一个八进制数: 51 八进制数 51 转二进制为 101001
kisushotto
kis***otto@163.com
//分别定义函数实现八进制转二进制 #include <stdio.h> int octTodeci(int num);//声明八进制转十进制函数 long long deciTobina(int num);//声明十进制转二进制函数 int powNum(int base,int exp);//声明求base的exp次方函数 void main() { int octNum, deciNum; long long binaNum; printf("Please enter an octal number:"); scanf("%d", &octNum); deciNum = octTodeci(octNum); binaNum = deciTobina(deciNum); printf("The conversion from octal number %d to binary number is %lld.\n%", octNum, binaNum); } int octTodeci(int num)//定义八进制转十进制函数 { int n = 0,remainder,result = 0; while (num != 0) { remainder = num %10; result += remainder*powNum(8, n); num /= 10; ++n; } return result; } long long deciTobina(int num)//定义十进制转二进制函数 { int remainder,n=0; long long result = 0; while (num != 0) { remainder = num % 2; result += remainder*powNum(10, n); num /= 2; ++n; } return result; } int powNum(int base,int exp)//定义求base的exp次方函数 { int result = 1,k; for (k = exp; k >= 1;--k) result *= base; return result; }kisushotto
kis***otto@163.com
ghjfgh
153***0114@qq.com
各种进制自由转换：
#include <stdio.h> #include <math.h> int aaaa(int num1, int num7);//声明转十进制函数 int ssss(int num2, int num6);//声明十进制转所求进制函数 int main() { int num1, num6; int num7; int num8; printf("请输入要转变的数字是几进位制的\n"); scanf_s("%d", &num7); printf("请输入%d进制数和要转变的进制数，中间用,隔开\n", num7); scanf_s("%d,%d", &num1, &num6); num8 = aaaa(num1, num7); ssss(num8, num6); return 0; } //定义八进制转十进制函数 int aaaa(int num1, int num7) { int i = 0; int k = 0; int num2 = 0, num3; while (num1 != 0) { if (num1 % 10 >= num7) { k++; printf("输入的%d进制数错误\n", num7); break; } num3 = num1 % 10; num2 = num2 + (int)pow(num7, i) * num3; num1 = num1 / 10; i++; } if (k == 0) { return num2; } return 0; } //定义十进制转二进制函数 int ssss(int num2, int num6) { int num4, num5 = 0; int j = 0; while (num2 != 0) { num4 = num2 % num6; num5 = num5 + (int)pow(10, j) * num4; num2 = num2 / num6; j++; } printf("转为%d进制数为%d\n", num6, num5); return 0; }ghjfgh
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