Python 练习实例85
题目:输入一个奇数,然后判断最少几个 9 除于该数的结果为整数。
程序分析:999999 / 13 = 76923。
程序源代码:
实例
#!/usr/bin/python
# -*- coding: UTF-8 -*-
if __name__ == '__main__':
zi = int(raw_input('输入一个数字:\n'))
n1 = 1
c9 = 1
m9 = 9
sum = 9
while n1 != 0:
if sum % zi == 0:
n1 = 0
else:
m9 *= 10
sum += m9
c9 += 1
print '%d 个 9 可以被 %d 整除 : %d' % (c9,zi,sum)
r = sum / zi
print '%d / %d = %d' % (sum,zi,r)
以上实例输出结果为:
输入一个数字: 13 6 个 9 可以被 13 整除 : 999999 999999 / 13 = 76923
Python 100例
叮咚
a12***59648z@qq.com
参考解法:
#!/usr/bin/python # -*- coding: UTF-8 -*- b=input('input a number:\n') a=9 n=1 while (1): if a%b==0: break else: a=a*10+9 n=n+1 print '%d 个 9 除于 %d 为整数' % (n,b)叮咚
a12***59648z@qq.com
du_solong
157***7972@qq.com
参考方法:
# -*- coding: utf-8 -*- """ Created on Fri Jun 30 17:08:43 2017 @author: zhangch """ """ 输入一个正整数,然后判断最少几个 9 除于该数的结果为整数。 """ if __name__ == "__main__": i = int(raw_input('input a number:')) sum = 9 while sum % i != 0: sum = sum * 10 + 9 print sumdu_solong
157***7972@qq.com
colinshi
col***shi@hotmail.com
参考方法:
#!/usr/bin/python3 # -*- coding: UTF-8 -*- def monkey(): a=int(input('输入一个数字:\n')) b=9 i=1 while True: if b > a and b%a==0: print('需要{}个9'.format(i)) break else: b = b*10+9 i+=1 if __name__ == '__main__': monkey()colinshi
col***shi@hotmail.com
Gagarin
fsi***771@gmail.com
参考方法:
# -*- coding: utf-8 -*- if __name__=='__main__': n=int(raw_input('输入数字:\n')) s=9 while True: if s%n==0: l = len(str(s)) print '%d 个 9 除于 %d 为整数' % (l,n) break else: st= str(s)+'9' s=int(st)Gagarin
fsi***771@gmail.com
pjdssjdcr
735***697@qq.com
参考方法:
# -*- coding: utf-8 -*- n = int(raw_input("n:")) j = 1 sum = 0 for i in range(20): sum += 9*j if (sum%n == 0): print sum,sum/13 break else: j = j*10pjdssjdcr
735***697@qq.com